拓扑排序的java实现

1497阅读 0评论2010-10-31 810
分类:Java

/*
 * @title:拓扑排序
 * @input: 一个有向无环图,表述为一个邻接矩阵graph[n][],其中graph[i][0]为顶点i的入度,其余为其后继结点
 * @output: 一个拓扑序列list
 */

import java.util.*;
public class TopologicalSortTest
{
   public static void main(String[] args)
   {
       int[][] graph={{0,1,2,3,},{2,},{1,1,4,},{2,4,},{3,},{0,3,4,},};
       int[] list=new int[graph.length];;
       TopologicalSort topologicalSort=new TopologicalSort();
       topologicalSort.input(graph);
       list=topologicalSort.getList();
       for(int l : list){
           System.out.print(l+" ");
       }
   }
}
class TopologicalSort
{
 int[][] graph;
 int[] list;
 
    void input(int[][] graph)
    {
     this.graph=graph;
     list=new int[graph.length];
     calculate();
    }
    
    void calculate()
    {
        Stack stack=new Stack();
        for(int i=0; i<graph.length; i++){
         if(graph[i][0]==0){
          stack.push(i);
         }
        }
        
        int i=0;
        while(stack.empty()!=true){
         list[i]=(Integer)stack.pop();
         for(int j=1; j<graph[list[i]].length; j++){
          int k=graph[list[i]][j];
          if((--graph[k][0])==0){
           stack.push(k);
          }
         }
         i++;
        }
        
        if(i<graph.length){
         System.out.println("存在环,不可排序!");
         System.exit(0);
        }
    }
    int[] getList()
    {
     return list;
    }
}


运行结果:
5 0 3 2 4 1
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