>>> s = [('a', 3), ('b', 2), ('c', 1)]
>>> sorted(s, key=lambda x:x[1])
[('c', 1), ('b', 2), ('a', 3)]
>>> max(s, key=lambda x:x[1])
('a', 3)
另有:
for i in args :
print i
fun1(1,2,3,4,5) # 结果是tuple.
fun1([1,2,3,4])
而kwargs 则返回dict.
def fun2(user=10,**kwargs) :
for k,v in kwargs.items() :
print k,v
fun2
fun2(user=1111,b=2,c=3,m=99999)