我有一个python 文件 megamon_connection.py, 这个文件里面定义了一个类，如下
class megamon_connection:
def connect_to_megamon(self, host, port, timeout, username, password):
oldcurrent = self._current
try:
self._current = TelnetConnection(host, port, self._prompt[:], timeout, "CR")
self._current.set_loglevel(self._loglevel)
self._current.un = username
self._current.pw = password
result = self._login(username, password)
if result:
found = re.search(r"<\s*$",result)
if found:
print "normal megamon via telnet"
except:
self._current = oldcurrent
raise
我在类外面定义了同名调用函数
def connect_to_megamon(host, port=23, timeout="30sec", user="SYSTEM", passwd="SYSTEM", msg=None):
"""This keyword opens a connection to a megamon system and logs in, now support telnet mode.
| Input Paramaters | Man. | Description |
| host | Yes | Identifies to host |
| port | No | Allows to change the default telnet port |
| timeout | No | Timeout for commands issued on this connection. Default is 120 sec |
| user | No | Authentication information |
| passwd | No | Authentication information |
| msg | No | |
Example
| Open Test | Connect To megamon | 10.69.248.247 |
"""
try:
conn = megamon_connection()
current = conn.connect_to_megamon(host, port, timeout, user, passwd)
except Exception, e:
megamon_error._raise_critical_exceptions(e)
if msg and msg.lower() != 'none':
raise AssertionError(msg)
else:
raise
global current_conn
current_conn = conn
return current
我在robot写了调用的case(已经在case中import 这个python文件)
Connect To Megamon ${HOST}
但是一直报错
Keyword 'megamon_connection.Connect To Megamon' expected 5 arguments, got 1.
这个问题查了半天，一直搞不明白，最后终于发现问题是，类名和文件名一样，直接调用到类里面的函数定义去了，没有调到外面的调用函数，所以又四个参数没有使用默认值，把类名或改文件名即可。