C语言实现双向循环链表

1030阅读 0评论2014-09-09 qizheguang
分类:LINUX

list

/* 双向循环链表,带头指针 */
struct list_node
{
    struct list_node *prev, *next;
};

/* 初始化头指针 */
void list_init_head(struct list_node* head)
{
    head->prev = head->next = head;
}

/* 量表是否为空 是返回1,否返回0 */
int list_is_empty(const struct list_node* head)
{
    return (head->prev == head) && (head->next == head);
}

/* 链表遍历 */
#define list_for_each(iter, head) \
    for (iter = (head)->next; iter != (head); iter = iter->next)

/* 链表逆序遍历 */
#define list_for_each_reverse(iter, head) \
    for (iter = (head)->prev; iter != (head); iter = iter->prev)

/* 链表遍历,支持删除操作 */
#define list_for_each_remove(iter, n, head) \
    for (iter = (head)->next, n = iter->next; iter != (head); iter = n, n = iter->next)

/* 求包含此链表的结构体指针 */
#define list_entry(ptr, type, member) \
    ((type *)((char *)(ptr)-(unsigned long)(&((type *)0)->member)))

static void __list_insert(struct list_node* node, struct list_node* prev, struct list_node* next)
{
    prev->next = next->prev = node;
    node->prev = prev;
    node->next = next;
}

/* 插入头节点 */
void list_push_front(struct list_node* head, struct list_node* node)
{
    __list_insert(node, head, head->next);
}

/* 插入尾节点 */
void list_push_back(struct list_node* head, struct list_node* node)
{
    __list_insert(node, head->prev, head);
}

static void __list_delete(struct list_node* prev, struct list_node* next)
{
    prev->next = next;
    next->prev = prev;
}

/* 移除节点 */
void list_remove(struct list_node* node)
{
    __list_delete(node->prev, node->next);
    node->prev = node->next = NULL;
}

/* 链表接合 将list接合到head,新链表的头节点仍为head */
void list_splice(struct list_node* head, struct list_node* list)
{
    if (list_is_empty(list) == 0)
    {
        list->next->prev = head;
        head->prev = list->next;

        list->prev->next = head->next;
        head->next->prev = list->prev;
    }
}

 

test

#include <stdio.h>
#include <malloc.h>
#include "list.h"

struct Stu
{
    int no;
    int age;
    struct list_node list;
};

int main()
{
    struct list_node* iter;
    struct Stu head;
    struct Stu* p;

    list_init_head(&head.list);

    int i = 5;
    while (i--)
    {
        struct Stu* stu = (struct Stu*)malloc(sizeof(struct Stu));
        if(stu != NULL)
        {
            stu->no = i;
            stu->age = i+3;
            list_push_back(&head.list, &stu->list);
        }
    }

    list_for_each(iter, &head.list)
    {
        p = list_entry(iter, struct Stu, list);
        printf("%d, %d\n", p->no, p->age);
    }

    printf("\nReversed list:\n");
    list_for_each_reverse(iter, &head.list)
    {
        p = list_entry(iter, struct Stu, list);
        printf("%d, %d\n", p->no, p->age);
    }

    struct list_node* iter_backup;
    list_for_each_remove(iter, iter_backup, &head.list)
    {
        p = list_entry(iter, struct Stu, list);
        list_remove(iter);
        free(p);
    }

    return 0;
}

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