python 监控 api 脚本

这个脚本的作用是: 访问 url,返回码大于500就发送报警邮件

主要用了 requests 模块, 所以跑监控脚本的 机器要先安装 requests
pip install requests

#!/usr/bin/env python
# -*- coding: utf-8 -*-

import smtplib
from email.mime.text import MIMEText
import sys
import requests


urls=[]
urls.append('')
urls.append('')


# 报警邮件参数设置, 前三行是用来发件的邮箱的配置
mail_host = 'smtp.exmail.qq.com'
mail_user = '[e-mail]' #qq邮箱这个地方必须写全！
mail_pass = "123456"
mail_postfix = 'suibianxie.com'
admin_email = '[e-mail]'




# 邮件发送函数
def send_mail(to_list,subject,content):
    me = mail_user+"<"+mail_user+"@"+mail_postfix+">"
    msg = MIMEText(content)
    msg['Subject'] = subject
    msg['From'] = me
    msg['to'] = to_list


    try:
        s = smtplib.SMTP()
        s.connect(mail_host)
        s.login(mail_user,mail_pass)
        s.sendmail(me,to_list,msg.as_string())
        s.close()
        return True
    except Exception,e:
        print str(e)
        return False


# 主体部分
for url in urls:
    try:
        r = requests.get(url,timeout=3)
        if r.status_code >= 500:
            msg = 'Error: ' + str(r.status_code) + ' ' + url
            print "send email"
            send_mail( admin_email,"api error",msg)
            print "done"
    except requests.exceptions.ConnectionError as e:
        print "These aren't the domains we're looking for."
    except requests.exceptions.ConnectTimeout as e:
        print "Too slow Mojo!"
    except requests.exceptions.HTTPError as e:
        print "And you get an HTTPError:", e.message

 之后放 crontab 里面运行就行