数据结构算法实现

1370阅读 0评论2014-04-08 xu2428847702
分类:C/C++

#include
#define M 20
/*
一维数组的倒置
数组a刚被调用时,调用的是数组的第一个数据,*a是可以直接代替数组a的,调用*a和调用数组a没多大的区别
*/
void fun(int *x,int n)
{
    int *p,m=n/2,*i,*j;
    i=x;
    j=x+n-1;
    p=x+m;
    for(;i     {
        int t=*i;
        *i=*j;
        *j=t;
    }
}
void main()
{
    int i,a[M],n;
    printf("Enter n:\n");
    scanf("%d",&n);
    printf("The original array:\n");
    for(i=0;i         scanf("%d",a+i);   //  a+i 就是数组a[i]
    fun(a,i);    //数组名a代表该数组首地址, 与&a[0]作用相同,*a即a[0]
    printf("\nThe array inverted:\n");
    for(i=0;i         printf("%d  ",*(a+i));
}
/* 一维数一维数组应用组应用 */
#include "stdio.h"
#include "stdlib.h"
void main()
{
    int  Employee[10]={27000,32000,32500,27500,30000,29000,31000,32500,30000,26000};
    int  Index;
    int  NewSalary;
    int  Selection;
    while(1)
    {
        printf("===================================================\n");
        printf("=Simple Employee Salary Management System         =\n");
        printf("=1.Display employee salary                        =\n");
        printf("=2.Modify employee salary                         =\n");
        printf("=3.Quit                                           =\n");
        printf("Please input your choose:");
        scanf("%d",&Selection);
        if(Selection==1||Selection==2)
        {
            printf("**Please input the employee number:");
            scanf("%d",&Index);
            if(Index<10)
            {
                 printf("**Employee Number is %d.",Index);
                 printf("The Salary is %d\n",Employee[Index]);
            }
            else
            {
                    printf("##The error employee number!\n");
                    exit(1);  // 需要stdlib.h头文件,表示异常退出.这个1是返回给操作系统的
            }
        }
        switch(Selection)
        {
            case  1:
                break;
             case   2:
                printf("**Please input new salary:");
                scanf("%d",&NewSalary);
                Employee[Index]=NewSalary;
                break;
             case    3:
                exit(1);
                break;
        }
        printf("\n");
   }
}
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