某些操作系统上没有 timeout 命令，那就写一个

话不多说，直接贴代码。

#include <stdio.h>
#include <stdlib.h>
#include <unistd.h>
#include <sys/wait.h>
#include <signal.h>

pid_t child_pid = -1;

void alarm_handler(int sig) {
    if (child_pid != -1) {
        kill(child_pid, SIGTERM);
    }
}

int isNumber(const char *s)
{
    int i = 0;
    for ( i = 0 ; i < strlen((const char *)s) ; i++)
    {
        if ( !isdigit(s[i]))
        {
            return 1;
        }
    }
    return 0;
}

int main(int argc, char *argv[]) {
    if (argc < 3) {
        fprintf(stderr, "Usage: %s   [args...]\n", argv[0]);
        return 1;
    } else if ( isNumber(argv[1]) != 0 )
    {
        fprintf(stderr, "Usage: %s   [args...]\n", argv[0]);
        return 1;
    }


    int timeout = atoi(argv[1]);
    if (timeout <= 0) {
        fprintf(stderr, "Timeout must be a positive integer\n");
        return 1;
    }

    signal(SIGALRM, alarm_handler);
    alarm(timeout);

    child_pid = fork();
    if (child_pid == 0) {
        // Child process
    if ( argc < 4 ){
             argv[3]=NULL;
    }
        execvp(argv[2], &argv[2]);
        perror("execvp");
        exit(1);
    } else if (child_pid > 0) {
        // Parent process
        int status;
        waitpid(child_pid, &status, 0);
        alarm(0); // Cancel the alarm
        return WIFEXITED(status) ? WEXITSTATUS(status) : 1;
    } else {
        perror("fork");
        return 1;
    }
}