用cut取出后两位

1. #!/bin/bash
   
2. for DATE in {20100731..20100802};do
   
3.         DAY=`echo $DATE | cut -b 7-`
   
4.         if [[ $DAY -le 31 ]] && [[ $DAY -ne 00 ]]; then
   
5.         echo $DAY
   
6.         fi
   
7. done

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